Last Updated January 6, 2019Comments about text by GopalanOther typographical errors appear in the EE 307 supplemental material packet |
Page | Where | Comment |
---|---|---|
10 | Fig. 1.4 | For an inverter,
VOH is the output voltage when the input
voltage is VOL,
not VIL. Please define VOH(MIN) as the output voltage when the input voltage is VIL. Similarly, VOL is the output voltage when the input voltage is VOH, not VIH. Please define VOL(MAX) as the output voltage when the input voltage is VIH. See revised figure. ![]() For a non-inverting buffer, adjust subscripts appropriately to obtain VOH(MIN) as the output voltage when the input voltage is VIH. |
12 | Eqn. 1.5 | 5 - 2(Vi - 1)2, for Vi between 1 and 2.35 V |
16 | Fig. 1.8 |
The low to high propagation delay, tPLH, measures the time elapsed between the 50% point on the input waveform and the 50% point on the output waveform. |
16 | last full ¶ | change form to from |
61 | last full ¶ | The equation should read I = (10 V - 0.6 V)/1.01 kOhm. |
66-67 | PSpice |
The PSpice input decks require a white space between Element
Name, Node 1, and Node 2 |
134 | Fig. P3.7c | Label 1 k ohm resistor between the +15V supply and the BJT collector RC. |
144 | 1st Eqn. | VC = VO = VBE(SAT) + (VCC - VBE(SAT))*(RB/N)/(RC + (RB/N)) |
179 | Table 4.2 | With 1.2 V < VIN < 1.5V, Q1 operates in Saturation. |
189 | 15th line | The collector is then clamped at 0.4 V BELOW the base, so the transistor can't saturate. |
192 | Fig. 4.29c | X-axis label should indicate VO vs. VI NOT VO vs. VO |
222 | last ¶ | vt = 2.6 mv should be vt = 26 mV |
228 | last line | 120 should be 120 mV |
240 | 9th line | -IERC1 = -0.93 V should be -IERC1 = -0.87 V |
240 | Equation after 9th line |
1.63 V should be -1.57 V |
279 | 4th line | =0.7 V should be = -0.7 V |
305 | Fig. 6.10 | RD = 1 kOhm |
308 | 3rd ¶ | "With gate and body connected together . . . ." should be "With gate and drain connected together . . . ." |
308 | 3rd ¶ | "Hence, the plot of sqrt(ID) = VGS in saturation . . . ." should be "Hence, the plot of sqrt(ID) vs. VGS in saturation . . . ." |
308 | 4th ¶ | "At VSG = 4V, substrate . . . ." should be "At VGS = 4V, substrate . . . ." |
309 | Fig. 6.16 | RD = 2 kOhm |
310 | 14th line | "using Equations (6.18) and (6.19)" should be "using Equations (6.12) and (6.19)" In fact, he should use Equations (6.12) and (6.20). |
339 | Fig 7.1c | Pinch-off should be Ohmic |
341 | After Eqn. 7.5a | dVo/dVi = 2Vo/ [2Vo + 1 - 2Vi] |
346 | Eqn. 7.22 | Replace KR by (KR)1/2 |
347 | Fig. 7.5a | VDSD should be VGSD |
381 | After Eqn. 7.67 | (See Figure 7.17e) |
398 | Eqn. 7.83 | 50[2(4 - VM)(5 - VX) - (5 - VX)2] = 50 (VX - VM - 1)2 |
398 | Last line | VSG = VDD should be VG = 0 V |
400 | Eqn. 2 & 3 | RHS has subscript "P" which should be "N" |
406 | Fig. 7.34a | MN2 is a NMOS, so the arrow should point from body (ground) to channel. |
408 | End of 2nd Paragraph | Delete the last sentence, because power dissipation takes place when M2 turns on, with the clock either high or low. |
416 | Last line | PMOSFET MP operates in the linear region. |
464 | Eq. 8.1 | IB1 has the units of mA. |
466 | 3rd line | Q3 should be QS instead |
473 | 2nd full ¶ | "saturation emitter current of Q1" should be "saturation emitter current of Q2" |
497 | Fig. 8.38 | Note that the output amplifier A is an inverting amplifier |
500 | Eqn. 8.30 | T = Ton + Toff = (RA + 2RB)C ln 2 |
562 | Last sentence | R/_W should be _R/W |